** RULES
OF VEDIC MATHEMATICS**

** **

*1. Ekadhikina
Purvena*

*COROLLARY**: **Anurupyena**
Meaning*: By one more than the previous one

*6. (Anurupye)
Shunyamanyat*

*COROLLARY**: **Vestanam** **
Meaning*: If one is in ratio, the other is zero

** **

**
Few of the
rules in detail**

** **

**EKĀDHIKENA PŪRVEŅA**

The
Sutra (formula) means: “*By one more than the previous one**”.
*

Now let us apply this sutra to the ‘

Consider
the example of 25^{2}.

Here the number is 25. We have to find out the square of the number. For the
number 25, the last digit is 5 and the 'previous' digit is 2. Hence, 'one more
than the previous one', that is, 2+1=3. The Sutra, in this context, gives the
procedure 'to multiply the previous digit 2 by one more than itself, that is,
by 3. It becomes the L.H.S (left hand side) of the result, that is,

2 X 3 = 6. The R.H.S (right hand side) of the result is 5^{2}, that is,
25.

__ __

**NIKHILAM NAVATAS’CHARAMAM DASATAH**

The
formula simply means : “** all from 9 and the last from 10**”

The formula can be very effectively applied in multiplication of numbers, which are nearer to bases like 10, 100, 1000 i.e., to the powers of 10(eg: 96 x 98 or 102 x 104). The procedure of multiplication using the Nikhilam involves minimum number of steps, space, time saving and only mental calculation. The numbers taken can be either less or more than the base considered.

**URDHVA TIRYAGBHYAM**

** **

*Urdhva
– tiryagbhyam*** **is the general formula applicable
to all cases of multiplication and also in the division of a large number by
another large number. It means “** Vertically and cross wise**.”

Now let us apply this sutra to “** Multiplication of two 2 digit numbers**”.

Ex. Find the product 14 X 12

SOL: Steps:

i) 4 X 6 = 24 : 2, the
carried over digit is placed below the second digit.

ii) (3 X 6) + (4 x 1)
= 18 + 4 = 22 ; 2, the carried over digit is placed below third digit.

iii) (2 X 6) + (3 X 1)
+ (4 X 3) = 12 + 3 + 12 = 27 ; 2, the carried over digit is placed below fourth
digit.

iv) (2 X 1) + ( 3 X 3)
= 2 + 9 = 11; 1, the carried over digit is placed below fifth digit.

v) ( 2 X 3 ) = 6.

vi) Respective digits
are added.

**YAVADADHIKAM TAAVADAHIKIKRITYA VARGANCHA YOJAYET**

** **

This
sutra means whatever the extent of its surplus, increment it still further to
that very extent; and also set up the square of that surplus. This sutra is
very useful in calculating the sqaures of numbers nearer(greater) to powers of
10.

For instance: in computing the square of 103 we go through the following steps:

1. The nearest power of 10 to 103 is 100.

2. Therefore, let us take 100 as our base.

3. Since 103 is 3 more than 100(base), we call 3 as the surplus.

4. Increase the given number further by an amount equal to the surplus.

i.e., perform ( 103 + 3 ) = 106. This is the left side of our answer!!.

5. On the right hand side put the square of the surplus, that is square of 3 =
09.

6. Append the results from step 4 and 5 to get the result.

Hence the answer is 10609.

** **

** **

** **

**ANTYAYOR DAŚAKE'PI**

The
Sutra simply means - numbers of which the last digits added up give 10.

This sutra is helpful in multiplying numbers whose last digits add up to 10(or
powers of 10). The remaining digits of the numbers should be identical.

EXAMPLE:**
57 X 53**

See the end digits sum 7 + 3 = 10 ; then by the sutras Antyayor dasakepi and Ekadhikena we have the answer.

Ekadhikena to the remaining digits means, increment the remaining digits by 1 and multiply it with the same.

57 x 53 = ( 5 + 1 )x5 / 7x3

= 3021.

__ __